How Zero Can Become Equal to One

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First of all, the following determinant’s value is zero.

| 0 1 0 |

| 1 0 1 |

|0 1 0 |

= 0 | 0 1 |    - 1 | 1 1 | + 0 | 1 0 |

| 1 0 |          | 0 0 |       | 0 1 |

= 0 – 0 + 0

= 0

Normally,

0 * 0 =1

But if we realize that one equation is repeated, we can get an interesting and happy coincidence.

The square matrix  becomes a rectangular one.





If we repeat the first row, we get a five on a die, or the stereographic projection for mm2.







If we manipulate the set of two rows, we can get some interesting comparisons to real results for the atomic triple of the proton, neutron, and electron.

First of all:

|101|

|010|

|101|

= 1*|10|

|01|

-          0*|00|

|11|

+1*|01|

|10|

=1-0-1

=0

= independence condition

|101|

|010|

=0

Placeholders of |p n e| for proton, neutron, and electron.

|101|=|p n e|=0

Or:

P+e=0=n

P=-e

Which corresponds to the charge condition for the proton and electron.

Note:





Really is:



2p +2e=0=n

Or:

2p=n

Or similarly:





n+n=0=2n=[chargeless condition of zero]

or:

2p +2n

Or the [4,2] series of [2n+2p, 2p]

Similarly,





Corresponds to the [2,1] series of [n+p,p].

Note that if we assume that



And



Are points, then these can define a straight line from:

[ x y z ] points of [1,0,1] and [0,1,0] or the corresponding vector.

(1-0,0-1,1-0)

=(1,-1,1)

=(p+,e-,no)

{note:   the position of the  placeholders changes slightly}

So that:

0*0 can become a straight line

{or a “vibrating string”, quantum mechanically }

So that:

0*0 <>0 and from the above derivation, probably “one” in some form or other.